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what i tend to do as a cross check is work out the per furlong time for each distance to make sure that each increasing distance is run slower per furlong. I knock off 13 seconds from each distance to alllow for standing start..then divide by the distance minus 1f

5f = 60.2 - 13 divide by 4 = 11.80
6f = 74.0 - 13 divide by 5 = 12.20
7f = 87.0 - 13 divide by 6 = 12.33
8f [R] = 100.5 - 13 divide by 7 = 12.50
8f = 99.0 -13 divide by 7 = 12.28
10f = 125.3 - 13 divide by 9 = 12.47
12f = 150.0 - 13 divide by 11 = 12.45

looking at those its clear that the 8f time is too difficult to equal..the per furlong time is faster than the 7f time..which isn't possible. The 10f & 12f times are also in question as they are very similar and are run faster than the 8f R time..which isn't possible

~~you will always struggle to get a fast time at 8f S using these imo~~

<blockquote data-quote="EC1" data-source="post: 2398468" data-attributes="member: 65360">what i tend to do as a cross check&nbsp; is work out the per furlong time for each distance to make sure that each increasing distance is run slower per furlong.&nbsp; I knock off 13 seconds from each distance to alllow for standing start..then divide by the distance minus 1f5f = 60.2 - 13 divide by 4 = 11.806f = 74.0 - 13 divide by 5 = 12.207f = 87.0 - 13 divide by 6 = 12.338f [R] = 100.5 - 13 divide by 7 = 12.508f <s> = 99.0 -13 divide by 7 = 12.28</s><s>10f = 125.3 - 13 divide by 9 = 12.47</s><s>12f = 150.0 - 13 divide by 11 = 12.45</s><s></s><s>looking at those its clear that the 8f <s> time is too difficult to equal..the per furlong time is faster than the 7f time..which isn&#039;t possible. The 10f &amp; 12f times are also in question as they are very similar and are run faster than the 8f R time..which isn&#039;t possible</s></s><s><s></s></s><s><s>you will always struggle to get a fast time at 8f S using these imo</s></s></blockquote>

[QUOTE="EC1, post: 2398468, member: 65360"] what i tend to do as a cross check is work out the per furlong time for each distance to make sure that each increasing distance is run slower per furlong. I knock off 13 seconds from each distance to alllow for standing start..then divide by the distance minus 1f 5f = 60.2 - 13 divide by 4 = [B]11.80[/B] 6f = 74.0 - 13 divide by 5 = [B]12.20[/B] 7f = 87.0 - 13 divide by 6 = [B]12.33[/B] 8f [R] = 100.5 - 13 divide by 7 = [B]12.50[/B] 8f [S] = 99.0 -13 divide by 7 = [B][COLOR="Red"]12.28[/COLOR][/B] 10f = 125.3 - 13 divide by 9 = [B]12.47[/B] 12f = 150.0 - 13 divide by 11 = [B][B]12.45[/B][/B] looking at those its clear that the 8f [S] time is too difficult to equal..the per furlong time is faster than the 7f time..which isn't possible. The 10f & 12f times are also in question as they are very similar and are run faster than the 8f R time..which isn't possible you will always struggle to get a fast time at 8f S using these imo[/S][/S] [/QUOTE]

Verification: 5 + 3 = ?